(CH_3)_3CBr + KOH (aq.) to (CH_3)_3COH + KBr. | vedclass

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Question

(A) The given reaction involves the conversion of a tertiary alkyl halide,$(CH_3)_3CBr$,into a tertiary alcohol,$(CH_3)_3COH$,using an aqueous base.Si

Vedclass · Accepted Answer

$SN^1$

Vedclass · Answer

(A) The given reaction involves the conversion of a tertiary alkyl halide,$(CH_3)_3CBr$,into a tertiary alcohol,$(CH_3)_3COH$,using an aqueous base.Since the substrate is a tertiary alkyl halide,the reaction proceeds via the formation of a stable carbocation intermediate.This mechanism is characteristic of the $SN^1$ (unimolecular nucleophilic substitution) reaction.Therefore,the correct option is $(a)$.

$(CH_3)_3CBr + KOH (aq.) \to (CH_3)_3COH + KBr$. The above reaction is:

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